Tangent Line Calculator
Enter a function of \( x \) (e.g., \( f(x) = \frac{1}{2}x^2 \)):
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How to use a Tangent Line Calculator?
Here are the steps to find the equation of the tangent line using the tangent line calculator provided above:
Step-1: Enter the Function:
- Input the function of x into the text field. For example, if your function is f\left(x\right)=\frac{1}{2}x^2 you would type 1/2*x^2
Step-2: Click “Calculate Tangent”:
- After entering the function, click the “Calculate Tangent” button.
Step-3: Enter x-Value:
- A prompt will appear asking you to enter the value of x where you want to find the tangent line.
Step-4: Provide x-Value:
- Input the desired value of x into the prompt and press Enter.
Step-5: View Tangent Line Equation:
- The calculator will display the equation of the tangent line at the specified x-value.
- The equation will be in the form y=mx+b, where m is the slope of the tangent line and b is the y-intercept.
How to find the equation of the tangent line?
To find the equation of a tangent line to a function at a given point, follow these steps:
Step-1: Find the Point (x, y):
- Substitute the given x-value into the function to find the corresponding y-value.
Step-2: Calculate the Derivative:
- Find the derivative of the function to determine the rate of change.
Step-3: Determine the Slope:
- Substitute the given x-value into the derivative to find the slope at that point.
Step-4: Use Point-Slope Formula:
- Substitute the point (x, y) and the slope into the point-slope formula to write the equation of the tangent line.
Example on the equation of a tangent line.
Find the equation of the tangent line for the function f(x)=x^2-5x+2 at x=3
Step-1: Find the point:
f(3)=3^2-5(3)+2
f(3)=9-15+2
f(3)=-4
The point on the graph at x=3 is (x_1,y_1)=(3, -4).
Step-2: Calculate the Derivative:
f'(x)=\frac{d}{dx}\left(x^2-5x+2\right)
f'(x)=2x-5+0
f'(x)=2x-5
Step-3: Determine the Slope:
f'(x)=2x-5
To find the slope of the tangent line, substitute x=3
m=2(3)-5
m=6-5
m=1
Step-4: Use Point-Slope Formula:
The point-slope form of the line is given by,
y-y_1=m(x-x_1)
y+4=1(x-3)
y+4=x-3
y=x-3-4
y=x-7
Therefore, the equation of the tangent line at x=3 is y=x-7
FAQs on finding the equation of a tangent line.
1) What is the equation of a tangent line?
Answer: The equation of a tangent line to a function at a specific point is a linear equation that represents the straight line that just touches the graph of the function at that point without crossing it.
2) How do you find the equation of the tangent line to a curve at a given point?
Answer: To find the equation of the tangent line to a curve at a given point, you need to find the slope of the curve at that point (By taking the derivative), and then use the point-slope form of an equation of line: y−y_1=m(x−x_1), where (x_1,y_1) is the given point and m is the slope of the tangent line.
3) What is the slope of the tangent line to a curve at a given point?
Answer: The slope of the tangent line to a curve at a given point is equal to the derivative of the function evaluated at that point.
4) Are there any special cases or techniques for finding tangent lines?
Answer: Yes, there are special cases such as when dealing with parametric equations or polar equations where specific techniques may be needed to find the equation of the tangent line.